# How do you solve #x=log_36 6#?

##### 1 Answer

Nov 30, 2015

Use the change of base formula and basic properties of logs to find:

#x = 1/2#

#### Explanation:

If

So:

#log_36 6 = (log 6)/(log 36) = (log 6)/(log 6^2) = (log 6) / (2 log 6) = 1/2#